Question: table [ [ x , 0 , 2 , 5 , 7 , 1 1 ] , [ f ( x ) , 1

\table[[x,0,2,5,7,11],[f(x),13,5,17,28,41]]
Selected values of a differentiable function f are given in the table above. What is the fewest possible number of values of c in the interval 0,11 for which the Mean Value Theorem guarantees that f'(c)=4?
Zero
One
Two
Three
\ table [ [ x , 0 , 2 , 5 , 7 , 1 1 ] , [ f ( x )

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