Take a look at the code below. What's going on here?

"void set$\_$number$\_$to$\_$three$($int number$)\{$

number $=3$;

return;

$\}$

int main$($void$)\{$

int number $=5$;

set$\_$number$\_$to$\_$three$($number$)$;

printf$("\%$d

$",$ number$)$;

return $0$;

$\}$

$"$

A: We would need to allocate space on the heap to make this work correctly.

B: We would need to pass a pointer into the function to make this work

correctly.

C: The function sets the specified number to $3.$

D: Segmentation fault. This is going to crash.