Question: Take the Laplace transform of the following initial value problem and solve for Y(s)=L{y(t)} : y^('')-4y^(')-32y=S(t),y(0)=0,y^(')(0)=0 where S is a periodic function defined by S(t)={(1,0=0.):}

Take the Laplace transform of the following initial value problem and solve for Y(s)=L{y(t)} : y^('')-4y^(')-32y=S(t),y(0)=0,y^(')(0)=0 where S is a periodic function defined by S(t)={(1,0=0.):} Hint: : Use the formula for the Laplace transform of a periodic function. Y(s)= The graph of S(t) (a square wave function)

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