Question: Task 01) Run the following code: void countDown(int num) { if (num == 0) // test System.out.println(Blastoff!); else { System.out.println(...); countDown(num-1); // recursive call )

 Task 01) Run the following code: void countDown(int num) \{ if

Task 01) Run the following code: void countDown(int num) \{ if (num == 0) // test System.out.println("Blastoff!"); else \{ System.out.println("..."); countDown(num-1); // recursive call ) \} what is the output of this code? - modify it so that it prints only the even numbers. - what is the time complexity of this algorithm and why? Task 02) Run the following code: int gcd( int x, int y){ if (x%y==0)// base case return y; else return gcd(y,x%y); \} what is the output of this code? - modify it to find the gcd using subtraction instead of \%. Task 03) Run the following code: int fib(int n ) \{ if (n

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