A crystal of Al(OH)3 is very slowly growing in a solution, so that Al(OH)3(s) ⇌ Al3+(aq) + 3OH-(aq) is essentially in equilibrium. For each of the following changes, discuss if the total mass of the Al(OH)3 crystal will increase, decrease, or remain unchanged.

a) The crystal splits into two halves, exposing the core (new surface area) to the solvent

b) Adding water (so there is a change in solution volume)

c) Adding 0.1M HCl(aq) (assume no change in solution volume)

Answer rating: 100% (QA)

a Cutting the crystal of AlOH into two halves will expose new surf... View the full answer