Question: Task 3 : Adaptive toggling delay We now modify the value of the delay between successive togglings, until 2 5 toggling operations have been executed.
Task : Adaptive toggling delay
We now modify the value of the delay between successive togglings, until toggling operations have been
executed. The program then prints a "task completed" message.
In main. c comment out task and uncomment task Open task and observe the code
provided.
Build and flash the application.
Observe that the program never executes the "task completed" print statement. What is the problem?
Correct the code to obtain the desired behavior. It should look similar to Figure
What is the effect of defining the delay variable as static? What would happen if we don't?
Terminal Terminal
SerialdevttyACMO : AM &s
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Congrat'si You completed task
Figure : Expected output of Task
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