Question: Task 4: Little and Long Lists <2.2.1 While-loops; 3.1 Strings; 2.1 Conditionals> Warm Up Let's start by learning about indexing. Indexing allows us to access
Task 4: Little and Long Lists
<2.2.1 While-loops; 3.1 Strings; 2.1 Conditionals>
Warm Up
Let's start by learning about indexing. Indexing allows us to access the ith element in a sequence. For example, if we have the list lst = ['a', 'b', 'c', 'd'] and we want to access the 'b' we can ask for lst[1]. Notice that Python indexes from 0. This means if we want the rst element in a sequence we have to ask for seq[0]. If the rst element is at 0, in our list lst what index is the last element? How could we write a loop that would look at every element?
Part A - Adding
Write a function add(numbers) that returns the sum of every second number in a given list. (E.g. calling add([2,-3,5,8,10,1]) returns 6 because 3 + 8 + 1 = 6.)
Part B - Flipping
Write a function flip(binary string) that takes a binary string (a string containing only 1s and 0s) and returns a new string where every bit has been ipped. (E.g. calling flip('001011') returns '110100'.
# Task 4
def add(numbers):
pass
def flip(binary_string):
pass
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