Task $4($Max points: $1)$

A rod made of plastic material $($see the diagram in the figure$)$ is subjected to longitudinal deformation according

to the law shown in the figure. Yield limit of dry friction element $Q(\frac{J}{m}3)E_1=E_2=8{}_0,{}_{\text{m}\text{a}\text{x}}=1\mathrm{.}01\frac{{}_0}{E_1},{}_0={10}^{8}Pa1\mathrm{.}975*{10}^{5}1\mathrm{.}875*{10}^{5}1\mathrm{.}575*{10}^{5}1\mathrm{.}675*{10}^5.$ Find the amount $of$ heat $Q(\frac{J}{m}3)$

dissipated $in$ the process under consideration. Let $E_1=E_2=8{}_0,{}_{\text{m}\text{a}\text{x}}=1\mathrm{.}01\frac{{}_0}{E_1},{}_0={10}^{8}Pa.$

$1\mathrm{.}975*{10}^5$

$1\mathrm{.}875*{10}^5$

$1\mathrm{.}575*{10}^5$

$1\mathrm{.}675*{10}^5$

Supplementary material:

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