Task 5. Rust is a common name for a large number of different types of iron...

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Task 5. Rust is a common name for a large number of different types of iron oxide and hydroxide. Pure iron has a strong affinity for reacting with oxygen, but exactly which corrosion product is formed depends on temperature, pH and moisture access. The following equations can be included in corrosion of iron: (a) Fe(OH)3(s)→→ FeO(OH)(s) + H₂O() (b) Fe2O3(s) + 3H₂O()→2Fe(OH)3(s) (c) 2FeO(OH)(s) → Fe2O3(s) + H₂O() - AG9 for process (a) is-31.3 kJ/mol and AG for process (c) is 1.7 kJ/mol. e for FeO(OH)(s)! Calculate G298 A) 179.0 kJ/mol B) -372.6 kJ/mol C) -490.6 kJ/mol D) 231.2 kJ/mol Q5: Q6: Calculate S298 for FeO(OH)(s)! A) 60 J/mol K B) 65 J/mol K ΔΗΘΕ = -24.3 kJ/mol 298 AH29 = 35.6 kJ/mol C) 69 J/mol K D) 73 J/mol K Task 5. Rust is a common name for a large number of different types of iron oxide and hydroxide. Pure iron has a strong affinity for reacting with oxygen, but exactly which corrosion product is formed depends on temperature, pH and moisture access. The following equations can be included in corrosion of iron: (a) Fe(OH)3(s)→→ FeO(OH)(s) + H₂O() (b) Fe2O3(s) + 3H₂O()→2Fe(OH)3(s) (c) 2FeO(OH)(s) → Fe2O3(s) + H₂O() - AG9 for process (a) is-31.3 kJ/mol and AG for process (c) is 1.7 kJ/mol. e for FeO(OH)(s)! Calculate G298 A) 179.0 kJ/mol B) -372.6 kJ/mol C) -490.6 kJ/mol D) 231.2 kJ/mol Q5: Q6: Calculate S298 for FeO(OH)(s)! A) 60 J/mol K B) 65 J/mol K ΔΗΘΕ = -24.3 kJ/mol 298 AH29 = 35.6 kJ/mol C) 69 J/mol K D) 73 J/mol K