Question: Task 8 - Hamming & SECDED Code (5+20= 25 marks) (a) (5 marks) For data, using 4 Hamming code parity bits determine the maximum number

Task 8 - Hamming & SECDED Code (5+20= 25 marks) (a)

Task 8 - Hamming & SECDED Code (5+20= 25 marks) (a) (5 marks) For data, using 4 Hamming code parity bits determine the maximum number of data bits that can be protected. (b) A SECDED encoded character has been retrieved, with the hexadecimal value of 51A16. You may assume that the SECDED parity is even. 1. (1 +4 marks) Was there an error in transmission? Explain your answer. 2. (15 marks) If there was an error, either correct it (reporting the corrected ASCII character) or explain why it could not be corrected (Show your Hamming/SECDED table)

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