Task A: Formulate the null and alternative hypothesis:

The principal of a certain high school claims that 85% of all the students is in

favor of the new school uniform. A Statistics teacher asked his students to

verify the claim. Suppose that 451 out of the 550 randomly selected

students indicated that they are in favor of the new school uniform. At 0.05

level of confidence, is there enough evidence to conclude that the

percentage of students who are in favor of the new uniform is different from

85%?

Answer:

Task B: Answer the following. (Just put your answer in the blanks). Some of the answers are given but if it's not correct, feel free to correct it.

1.)

Electrolux Incorporated manufactures and sells home products for the last

25 years. They claim that their vacuum cleaner disburses a mean of 46 kilowatt

hour/year. In a survey conducted by business students, 12 homes were asked and responses indicated that vacuum cleaners produced by Electrolux disburse a mean of 42-kilowatt hour per year with a standard deviation of 11.9 kilowatt-hours. Can we conclude at the 0.05 level of significance that Electrolux vacuum cleaners disburse, on the average, less than 46 kilowatt-hours per year? Assume the

population of kilowatt-hours to be approximately normal.

Given: n = 12

Sample mean = 42

s = 11.9

u = 46

a = 0.05

Answer the ff:

~Formulate the null and alternative hypothesis: ___________

~ Specify the level of significance: a= 0.05 (One tailed to the left)

~ Choose the appropriate test statistic.

NOTE: (The number of samples is 12 and 12 is less than 30): ___________

~ Establish the critical region: t critical values: -2.201

Solution: _____

~ Compute for the value of the test statistic:

Answer: __

Solution: __

~ Make a decision and interpret the result: -1.10 > -2.201

The null hypothesis is failed to reject.

So, there is no significant difference between the sample mean and the population mean.

Therefore, the claim is true.

2.) Henry See, an owner of a shopping mall in the country wants to determine

whether the mean income of families living within 2 miles of a proposed location of

a mall exceeds Php 24 400. At the 0.05 level of significance, what can be conclude

if the mean income of a random sample of 60 families living within 2 miles of the

proposed location of the mall is Php 24 524 and the standard deviation is Php 763.

Given: n = 60

Sample mean = 24,524

s = 763

u = 24,500

a = 0.05

Answer the ff:

~Formulate the null and alternative hypothesis: ___________

~ Specify the level of significance: a= 0.05 (One tailed to the right)

~Choose the appropriate test statistic.

NOTE: (The number of samples/families is 60 and 60 is greater than 30): _________

~ Establish the critical region: Z critical values: 1.96

Solution: _

~ Compute for the value of the test statistic

Ans: ____

Solution:____

~Make a decision and interpret the result: 0.24 < 1.96. The null hypothesis failed to reject. So, there is no significant difference

between the sample mean and the

population mean. Therefore, the claim is

true.

Reminder: You can correct anything if there's something wrong. Thank u.