Tem took 1.00 ml of seawater and diluted it to 125.00 ml of distilled water. He...
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Tem took 1.00 ml of seawater and diluted it to 125.00 ml of distilled water. He titrated the sample with 0.004501 M EDTA. It took 15.25 mL of 0.004501 M EDTA to reach endpoint. What is the ppm CaCO3 of his water sample? MW of CaCO3 = 100.09 g/mole. 1000 mg = 1 gram (5] %3D 100.095 Tem took 1.00 ml of seawater and diluted it to 125.00 ml of distilled water. He titrated the sample with 0.004501 M EDTA. It took 15.25 mL of 0.004501 M EDTA to reach endpoint. What is the ppm CaCO3 of his water sample? MW of CaCO3 = 100.09 g/mole. 1000 mg = 1 gram (5] %3D 100.095
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Toms water sample has 5496 ppm CaCO3 since molanity of EDTA 000 4501 M 100... View the full answer
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