Question: Test Benson Racing is training a new pit crew for its racing team For its first practice run, the pit crew is able to compite

Test Benson Racing is training a new pit crew for
Test Benson Racing is training a new pit crew for
Test Benson Racing is training a new pit crew for its racing team For its first practice run, the pit crew is able to compite all the tasks in exactly 40 seconds not exactly world-class. The second time around the crew shaves 10 seconds off its time, Click the icon to view the learning curves table. a. The estimated teaming rate for the pit crew is (Enter your response as a whole number) b. Mark Benson, owner of Benson Racing, says that the pit crew must be able to complete all the tasks in less than 19.2 seconds in order to be competitive. Based on the answer to parta, how many times will the pit crew need to practice before it breaks the 19.2-second barrior? Pt crew need to practice times. (Enter your response as a whole number) C. Ist roolistic to expect the pit crew to experience learning improvements indefinitely? Question Vimer OA. Yes, it is realistic to expect indefinite learning improvements because learning curve theory suggests OB. No, it is not realistic to expect indefinite learning improvements because there are other limitations on the time it takes to complete the task besides the Knowledge of the pit crew. OC. Yes, it is realistic to expect indefinite learning improvements because there are no other limitations on the time it takes to complete the task besides the Unit number 123456789p=28H 70% learning nb 1.000 0.700 0.568 0.490 0.437 0.398 0.367 0.343 0.323 0.306 0.291 0.278 0.267 0.257 75% learning nb 1.000 0.750 0.634 0.563 0.513 0.475 0.446 0.422 0.402 0.385 0.370 0.357 0.345 0.334 80% learning no 1.000 0.8 0.702 0.640 0.596 0.562 0.534 0.512 0.493 0.477 0.462 0.449 0.438 0.428 85% learning nb 1.000 0.850 0.773 0.723 0.686 0.657 0.634 0.614 0.597 0.583 0.570 0.558 0.548 0.539 90% learning nb 1.000 0.900 0.846 0.810 0.783 0.762 0.744 0.729 0.716 0.705 0.695 0.685 0.677 0.670

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