Question: TEST: def check(num_string): print(num_string, end=' is ') if not valid_float(num_string): print(end='not ') print('valid') test_values = 0.6 00.6 .6 -0.6.split() for number in test_values: check(number) RESULT:

 TEST: def check(num_string): print(num_string, end=' is ') if not valid_float(num_string): print(end='not

TEST:

def check(num_string): print(num_string, end=' is ') if not valid_float(num_string): print(end='not ') print('valid') test_values = "0.6 00.6 .6 -0.6".split() for number in test_values: check(number)

RESULT:

0.6 is valid 00.6 is not valid .6 is not valid -0.6 is valid

The function has this signature def valid float (number_string) Check whether a string consists only of decimal digits (of any length) and the "- and"." characters and matches the following requirements. The function returns True if the string is valid, and False otherwise. The string must start with a decimal digit or "-". The"-" can only occur as the first character if it appears at all. If the first decimal digit is a "O" the next character must be".". The string does not have to include a"." There can be only one". in the string. If the string includes a." there must be a string of 1 or more decimal digits before the"."and there must be 1 or more decimal digits after the"." These strings are valid: 1234 -1234 12.4 -1234567890.123456789 These strings are invalid: +123 123 00.6 12-.6335

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!