Test: Exam: Module 5 Question 4 of 10 This test: 10 point(s) possible This question: 1 point(s) possible Submit test A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (KWh). You want to test this claim. You find that a random sample of 68 residential customers has a mean monthly consumption of 890 KWh. Assume the population standard deviation is 128 KWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H. . Choose the correct answer below. O A Ho: HS 890 O B. Ho: H = 870 (claim) Ha: H > 890 (claim) Ha: H #870 O C. Ho: HS 870 OD. Ho: H = 890 Ha: H > 870 (claim) Ha: H # 890 (claim) O E. Ho: H > 870 (claim) OF Ho: H > 890 (claim) Ha H S 870 Ha: H S 890 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical values are +. O B. The critical value is Identify the rejection region(s). Select the correct choice below. A. The rejection regions are z 1,64. O B. The rejection region is z 1.64. (c) Find the standardized test statistic, Use technology. The standardized test statistic is z= (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. 18 Paiart H. hersues the standardized test statistic is not in the ralasting ranian Time Remaining: 01:22:39 Next