Test: Week 2 Test ... Question 17 This Test: 100 pts possible Submit Test Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a beachball with a diameter of 36.6 cm. How does the result compare to the actual circumference of 115.0 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 7.4 23.7 4.4 21.7 6.9 3.9 20.6 Circumference 23.2 74.5 13.8 68.2 21.7 12.3 64.7 Click the icon to view the critical values of the Pearson correlation coefficient r. . . ... The regression equation is y = ]+x. (Round to five decimal places as needed.) The best predicted circumference for a diameter of 36.6 cm is cm. (Round to one decimal place as needed.) How does the result compare to the actual circumference of 115.0 cm? A. Since 36.6 cm is beyond the scope of the sample diameters, the predicted value yields a very different circumference. O B. Even though 36.6 cm is within the scope of the sample diameters, the predicted value yields a very different circumference. O C. Even though 36.6 cm is beyond the scope of the sample diameters, the predicted value yields the actual circumference. O D. Since 36.6 cm is within the scope of the sample diameters, the predicted value yields the actual circumference