Question: Consider the function h(x). If h(x) has removable discontinuity, how the second piece is to be redefined so that h(x) becomes continuous? 2- 2r
Consider the function h(x). If h(x) has removable discontinuity, how the second piece is to be redefined so that h(x) becomes continuous? 2- 2r - 15 x + -3 h(x) = x + 3 -6, x = -3 O The discontinuity cannot be removed. h(x) = - 8 for x = - 3 h(x) = -2 for x = - 3 O h(x) is a continuous function for all real values of 'x'
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