th square. Evaluate the iterated integral and compare it with the approaimation, $($Round your answers bo ase decimal place.$)$

$\frac{1}{4}{\displaystyle \underset{0}{\overset{4}{}}}{\displaystyle \underset{0}{\overset{2}{}}}{x}^{2}ydydx$

${\displaystyle \underset{i=1}{\overset{1}{}}}(x,y)A_i$

$\frac{1}{4}{\displaystyle \underset{0}{\overset{4}{}}}{\displaystyle \underset{0}{\overset{2}{}}}{x}^{2}ydydx=$

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