Identify the surface whose equation is given. 6r + z = 1 an ellipsoid centered at...

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Identify the surface whose equation is given. 6r² + z² = 1 an ellipsoid centered at the origin with intercepts x = = ± ¹₁, y = + ¹,₁ z = ±1 an ellipsoid centered at the origin with intercepts x = ± # 7/7/6 ₁² Y = = = 7/16/₁ y a cylinder centered at the origin with intercepts x = ±- = ± 1/₁, y = ± 1, z = Z = ±1 a sphere centered at the origin with intercepts x = ±1, y = ±1, z = ±1 1 a cylinder centered at the origin with intercepts x = ± = = √7/6 ₁ Y = ± √ 6 ₁ ² y z = +1 Z = +1 X Identify the surface whose equation is given. 6r² + z² = 1 an ellipsoid centered at the origin with intercepts x = = ± ¹₁, y = + ¹,₁ z = ±1 an ellipsoid centered at the origin with intercepts x = ± # 7/7/6 ₁² Y = = = 7/16/₁ y a cylinder centered at the origin with intercepts x = ±- = ± 1/₁, y = ± 1, z = Z = ±1 a sphere centered at the origin with intercepts x = ±1, y = ±1, z = ±1 1 a cylinder centered at the origin with intercepts x = ± = = √7/6 ₁ Y = ± √ 6 ₁ ² y z = +1 Z = +1 X

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Solution The given equation is 641 2 1 z using 12 or ... View the full answer