Question: The 2 3 4 0 0 0 - lb space - shuttle orbiter touches down at about 2 3 9 mi / hr . At

The 234000-lb space-shuttle orbiter touches down at about 239 mi/hr. At 205 mi/hr its drag parachute deploys. At 38 mi/hr, the chute is jettisoned from the orbiter. If the deceleration in feet per second squared during the time that the chute is deployed is -0.00037v^2(speed vin feet per second), determine the corresponding distances traveled by the orbiter. Assume no braking from its wheel brakes. Answer: s= i ft

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