The acceleration $($a vector quantity$)$ of gravity on a sky diver is $9\mathrm{.}8\frac{m}{s^2}.$ If the force of the wind also causes an acceleration of $2\mathrm{.}4\frac{m}{s^2}$ at an angle of $17$ above the horizontal, what is the resultant acceleration of the sky diver?

Set up the problem by representing each force as a vector. Let $S$ represent the downward force on the sky diver due to gravity, let $W$ represent the upward force on the sky diver due to the wind, and let $R$ represent the resultant vector.

$\backslash$table$[[$Vector$,$Magnitude,Standard$-$position Angle$],[$S$,,$grad,$],[$W$,,$grad,$]]$