The alternatives shown are to be compared on the basis of their present worth values. At an interest rate of 10% per year, the values of n that you should use in the uniform series factors to make a correct comparison by the present worth method are: 05 (2 Points) Alternative A Alternative B First cost, $ Annual operating cost, $ per year Salvage value, $ -50,000 - 10,000 -90,000 -4000 13,000 3 Life, years 15,000 6 n = 6 years for A and n = 6 years for B None of the answers O n = 3 years for A and n = 6 years for B n = 3 years for A and n = 3 years for B