The amortized per$-$operation runtime of mm insertions into a min$-$heap followed by nn removeMin operations is:

Choice $1$ of $8$:$($n$2)($n$2)$Choice $2$ of $8$:$($log$($log n$)$n$)$Choice $3$ of $8$:$($m$2)($m$2)$Choice $4$ of $8$:$($n$+$m$)($n$+$m$)$Choice $5$ of $8$:$($log$($log m$)$m$)$Choice $6$ of $8$:$($n$($n loglog n$)$n$)$Choice $7$ of $8$:$(($n$+$m$)(($n$+$m$)$ loglog m$)$m$)$Choice $8$ of $8$:$($n$)($n$)$