The amount of Fe in a 0.4891-g sample of an ore was determined by titrating with...

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The amount of Fe in a 0.4891-g sample of an ore was determined by titrating with K₂Cr₂O₂. After dissolving the sample in HCI, the iron was brought into the +2 oxidation state using a Jones reductor. Titration to the diphenylamine sulfonic acid end point required 36.92 mL of 0.02153 M K₂Cr₂O₂. Report the ore's iron content as % w/w Fe₂O₂. Cr₂0,² + 14H+ + 6e → 2Cr³+ + 7H₂O Fe²+ Fe + e The amount of Fe in a 0.4891-g sample of an ore was determined by titrating with K₂Cr₂O₂. After dissolving the sample in HCI, the iron was brought into the +2 oxidation state using a Jones reductor. Titration to the diphenylamine sulfonic acid end point required 36.92 mL of 0.02153 M K₂Cr₂O₂. Report the ore's iron content as % w/w Fe₂O₂. Cr₂0,² + 14H+ + 6e → 2Cr³+ + 7H₂O Fe²+ Fe + e

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Answer The overall balanced equation will be given by combining the two given half reaction... View the full answer