Question: The angular position of a point on a rotating disk is given by 9 = (-0.08) + (0.37) + (4.42) t + (48), where

The angular position of a point on a rotating disk is given by 9 = (-0.08) + (0.37) + (4.42) t + (48), where 0 is in radians and t is in seconds. What is its angular acceleration in rad/s at t = 45 sec? Round your answer to two decimal places.

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