Question: The angular speed of a point following a circular path with radius r = 0.128 m can be described by the equation: a= 9.12t +

The angular speed of a point following a circular path with radius r = 0.128 m can be described by the equation: a= 9.12t + 7.65 rad/s. Part 1) Write an expression for the angular acceleration of the point. rad/s = Part 2) Between t = 1.78 s and t = 2.63 s, what total angle is the point displaced through? 0 = radians Part 3) At 1.78 s, what is the magnitude of the translation acceleration?

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