The answer for $10-46$ is y bar $=1\mathrm{.}29$ in$,$ Ix bar $=6\mathrm{.}74$ in$^4$ and for $10-47$ it is Iy bar $=18\mathrm{.}3$ in$^4$ but I$\text{'}$m confused how they got there. can you show me the work?

$10-46.$ Determine $\frac{?}{\text{b}\text{a}\text{r}}(y)$ which locates the centroid $C$ of the cross$-$sectional area of the wing channel, and then determine the moment of inertia $\frac{?}{\text{b}\text{a}\text{r}}(I{)}_{x^{\text{'}}}$ about the centroidal $x^{\text{'}}$ axis. Neglect the effect of rounded corners. The material has a uniform thickness of $0\mathrm{.}5$ in $.$

$10-47.$ Determine the moment of inertia of the cross$-$sectional area of the wing channel about the $y$ axis.

Problems $10-46/4$