The assignment asks for hand-written notes to keep it simple, HOWEVER, feel free to write in MS Word or Excel as appropriate. Just make sure it's readable, please! Step One: Use the data below, hand draw an AON network diagram and calculate Forward Pass, Backward Pass, Slack Time and Critical Path. Clearly identify your critical path. Step Two: You have only 16 days to complete this project. What is the least cost solution to achieve completion in 16 days? Redraw a second AON network diagram by hand showing completion of the network in 16 days and calculate Forward Pass, Backward Pass, Slack Time and Critical Path(s). Example - "maximum crash time" interpretation, Activity B Activity B can be done in the standard 5 days, or crashed a maximum of 2 days Activity B cannot be done in 1 or 2 days, the minimum duration is 3 days If the duration is shortened to 4 days from 5, the additional cost is $60 If the duration is shortened to 3 days from 5, the additional cost is $120. Step Three: Show your calculations to arrive at the least cost increase to achieve the 16 day duration Activity Preceding Duration Max Crash Cost per day to crash it ID Activity in Days Time . A None 3 1 $20 B A 5 2 $60 C A 3 1 $40 D A 10 0 $0 E B 6 3 $50 F C 7 3 $100 G D,E,F 5 1 $70 Step Four: Submit the two hand drawn AON networks diagrams (Steps 1 and 2) along with your hand written calculations your name and signture, scan them and place them in a Word document, and submit them to the the Dropbox. Grading: Step 1 Step 2 Step 3 3 3 3 Step 4 instructions 1 Total 10 Step 1: Air Control Company-AON 3 B 8 8 0 0 A 3 3 3 3 5 8 3 C 6 8 6 14 6 F 13 14 1 4 3 7 3 D 13 1 4 14 0 1 0 E 7 G 19 14 5 19 ID EF 0 7 14 Legend 10 14 ES SL Description LS Dur LF Critical Path =A + B + E +G Example of a Critical Path = A + B +C 2 E SW Develop. 20 22 18 40 Step One: 3 1 4 0 0 0 3 3 0 3 A 3 3 3 1 4 6 6 1 7 C 3 7 8 8 0 8 B 5 8 13 F 7 14 14 E 6 14 13 D 10 Critical Path: A-B-E-G The project duration for the projec 14 Step Two: Activity ID Cost per day to crash ($) Normal Time (days) A B C D E F G 20 60 40 0 50 100 70 3 5 3 10 6 7 5 Max Crash Crash Cost Time ($) 1 2 1 0 3 3 1 20 120 40 0 150 300 70 The normal project completion time is 19 days, and we have To shorten a project, only critical activities are crashed in ord From, the least cost solution to reduce the project duration Step Three: Option -1: Crash A & B Option -2: Crash B & G Cost per Activity ID day to crash ($) Activity ID Cost per day to crash ($) G B 70 60 A B 20 60 Normal Max Crash Crash Cost Time Time ($) (days) 3 5 1 2 3 $20 $120 $140 a. Crash Activity A by 1 day = 1 * $20 = $20 b. Crash Activity B by 2 days = 2 * 60 = $120 => Total Cost of Crashing = $20 + $120 = $140 Step Four: Normal Max Crash Crash Cost Time Time ($) (days) 5 5 1 2 3 $70 $120 $190 As we crashed the Activity A and Activity B, the durations will now be A: 2 days and B: 3days After crashing Activity A & B, we now have two critical paths with 17 days of project duration. 2 0 2 0 0 0 2 2 1 3 A 2 2 2 0 2 Activity ID Cost per day to crash ($) Normal Time (days) A B C D E F G 20 60 40 0 50 100 70 2 3 3 10 6 7 5 5 C 3 5 5 B 3 6 5 0 5 5 1 6 12 F 7 12 11 E 6 12 12 D 10 12 Max Crash Crash Cost Time ($) Available 0 0 1 0 3 3 1 $0 $0 $40 $0 $150 $300 $70 Critical Path-1: A-C-F-G: 17 days Critical Path-2: A-D-G: 17 days Both critical paths need to be shortened, otherwise Crashing Activity G by 1 day, because it is on both th The crash cost per day for Activity G is $70 The updated path times are: Critical Path-1: A-C-F-G: 16 days Critical Path-2: A-D-G: 16 days And, total crashing cost = $140 + $70 = $210 14 0 14 19 G 5 Activity ID Duration in Days (t) Earliest Start Latest Start Earliest Finish (ES + t) A B C D E F G 3 5 3 10 6 7 5 0 3 3 3 8 6 14 0 3 4 4 8 7 14 3 8 6 13 14 13 19 19 cal Path: A-B-E-G project duration for the project activity is 19 days. n time is 19 days, and we have only 16 days to complete the project. Therefore, 3 days have to be reduced. cal activities are crashed in order to reduce the project duration. Let's check the cheapest options. o reduce the project duration by 3 days it to crash activities A & B (Option-1) Option -3: Crash E Activity ID Cost per day to crash ($) E 50 Normal Max Crash Crash Cost Time Time ($) (days) 6 3 $150 3 $150 2 days and B: 3days s of project duration. 12 0 12 17 G 5 17 Crashed ed to be shortened, otherwise the length of the project remains unchanged. y 1 day, because it is on both the critical paths y for Activity G is $70 st = $140 + $70 = $210 Latest Finish Slack (LS - ES) On Critical Path 3 8 7 14 14 14 19 0 0 1 1 0 1 0 Yes Yes No No Yes No Yes