The Circuit shows a Boost Converter with energy storage or filter inductor L. Assume continuous conduction....

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The Circuit shows a Boost Converter with energy storage or filter inductor L. Assume continuous conduction. The circuit operating conditions are shown in the figure: 6000 Pa A 3 4000 3000 2000 Boost Converter circuit The Core material is a Ferrite known as N97 with saturation near Bm=0.4T (See below). 1000 iL-10A 00 + UL Vd=10V f<10 kHz 25 °C <--- 100 °C MOSFET D FALO618-E 100 200 300 400 mT 500 550 B A mT 400 300 200 io 100 R FALO619-M -200 0 200 400 600 800 1000 A/m 1400 Dynamic magnetization curves (typical values) (f = 10 kHz, T = 25 °C) The MOSFET Turn ON duty cycle is 50% with Switching Frequency at 50kHz. If the desired inductance is appro mately L=1mH, assuming negligible inductor current ripple, a. Find the required area product. b. Choose your core from Table 1 of the notes and calculate the number of winding turns and the wire gauge. You may use a window utilization factor of Ku=40% and RMS- Current density 250A/cm². c. Find the required total air-gap (the physical air-gap between cores is halved if the side core limbs have also the gap). You may make the approximation that the core Reluctance is negligible. d. The source voltage Va is increased and it increases to the point where the core saturates. What will happen to the supply current (i.e. Inductor current) as the core saturates? The Circuit shows a Boost Converter with energy storage or filter inductor L. Assume continuous conduction. The circuit operating conditions are shown in the figure: 6000 Pa A 3 4000 3000 2000 Boost Converter circuit The Core material is a Ferrite known as N97 with saturation near Bm=0.4T (See below). 1000 iL-10A 00 + UL Vd=10V f<10 kHz 25 °C <--- 100 °C MOSFET D FALO618-E 100 200 300 400 mT 500 550 B A mT 400 300 200 io 100 R FALO619-M -200 0 200 400 600 800 1000 A/m 1400 Dynamic magnetization curves (typical values) (f = 10 kHz, T = 25 °C) The MOSFET Turn ON duty cycle is 50% with Switching Frequency at 50kHz. If the desired inductance is appro mately L=1mH, assuming negligible inductor current ripple, a. Find the required area product. b. Choose your core from Table 1 of the notes and calculate the number of winding turns and the wire gauge. You may use a window utilization factor of Ku=40% and RMS- Current density 250A/cm². c. Find the required total air-gap (the physical air-gap between cores is halved if the side core limbs have also the gap). You may make the approximation that the core Reluctance is negligible. d. The source voltage Va is increased and it increases to the point where the core saturates. What will happen to the supply current (i.e. Inductor current) as the core saturates?

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Answer 1 MSK is Minimum shif Keying 2Like GPsk it also used Symbols having ... View the full answer