The circular cantilever beam shown below is loaded with an alternating axial load of 4 kN....

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The circular cantilever beam shown below is loaded with an alternating axial load of 4 kN. It is also loaded with a constant transverse load of 100 N and a torque that goes from 0 to 400 N-m. The material is ductile and the endurance limit fully corrected as appropriate for this problem is 0.120 GPa. The yield strength is 0.200 GPa. The ultimate strength is 0.700 GPa. The length is 1 m and the diameter is 0.1 m. Geometric stress concentration factors where the cylinder connects to the wall are not shown in the figure but have been computed to be Kt bending = 3.2, Kt axial 2.5, and Kt torsion = 2.0. The notch radius for bending and axial loading is 1.5 mm. The notch radius for torsion is 1.0 mm. The material has a body centered cubic microstructure. Dia. = 0.1 m Torque is 0-400 N - m Alternating NOT reversed 1 m A. 3.44e6 Pa 100 N Constant 11. Compute the alternating stress to be used in the Goodman failure equation. (10 pts) B. 4.86e6 Pa 4 kN Alternating Completely reversed A. 1.42e6 Pa B. 3.27e6 Pa C. 6.73e6 Pa D. 8.21e6 Pa 12. Compute the mean stress to be used in the Goodman failure equation. (10 pts) C. 4.24e6 Pa D. 6.44e6 Pa E. Other Specify E. Other specify = The circular cantilever beam shown below is loaded with an alternating axial load of 4 kN. It is also loaded with a constant transverse load of 100 N and a torque that goes from 0 to 400 N-m. The material is ductile and the endurance limit fully corrected as appropriate for this problem is 0.120 GPa. The yield strength is 0.200 GPa. The ultimate strength is 0.700 GPa. The length is 1 m and the diameter is 0.1 m. Geometric stress concentration factors where the cylinder connects to the wall are not shown in the figure but have been computed to be Kt bending = 3.2, Kt axial 2.5, and Kt torsion = 2.0. The notch radius for bending and axial loading is 1.5 mm. The notch radius for torsion is 1.0 mm. The material has a body centered cubic microstructure. Dia. = 0.1 m Torque is 0-400 N - m Alternating NOT reversed 1 m A. 3.44e6 Pa 100 N Constant 11. Compute the alternating stress to be used in the Goodman failure equation. (10 pts) B. 4.86e6 Pa 4 kN Alternating Completely reversed A. 1.42e6 Pa B. 3.27e6 Pa C. 6.73e6 Pa D. 8.21e6 Pa 12. Compute the mean stress to be used in the Goodman failure equation. (10 pts) C. 4.24e6 Pa D. 6.44e6 Pa E. Other Specify E. Other specify =