The code example below lead to deadlock between two threads.

$I^{**}$ thread$\_$one runs in this function $*\frac{*}{?}$

void $*$do$\_$work$\_$one$($void $*$param$)$

$\{$

pthread$\_$mutex$\_$lock$($&first mutex$)$;

pthread$\_$mutex$\_$lock$($&second$\_$mutex$)$;

$J^{****}$

Do some work

$*/$

pthread$\_$mutex unlock $($&second mutex$)$;

pthread$\_$mutex$\_$unlock$($&first mutex$)$;

$\}$

pthread$\_$exit $(0)$;

$1^{**}$ thread$\_$two runs in this function $*\frac{*}{?}$

void $*$do work two$($void $*$param$)$

i

pthread mutex lock $($&second mutex$)$;

pthread$\_$mutex$\_$lock$($&first$\_$mutex$)$;

$J^{****}$

Do some work

$*$I

pthread mutex unlock $($&first mutex$)$;

pthread mutex unlock $($&second mutex$)$;

$\}$

pthread exit $(0)$;

will not

can

always

will