Question: The coding language is Python. 7. [6] For each piece of code on the left, identify the corresponding output displayed on the right a) x,
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The coding language is Python.
7. [6] For each piece of code on the left, identify the corresponding output displayed on the right a) x, y = [ 1, 2, 3, 4, 5, 6], [] print (x, y) while x != [] : y.insert(0, x.pop()) print (x, y) 1) [1, 2, 3, 4, 5, 6] [] [1, 2, 3, 4, 5] [6] [1, 2, 3, 4] [5, 6] [1, 2, 3] [5, 4, 6] [1, 2] [5, 3, 4, 6] [1] [5, 3, 2, 4, 6] [] [5, 3, 1, 2, 4, 6] 2) b) x, y = [ 1, 2, 3, 4, 5, 6], [] print (x, y) while x != [] : y.append(x.pop()) print (x, y) [1, 2, 3, 4, 5] [6] [1, 2, 3, 4] [6, 5] [1, 2, 3] [4, 6, 5] [1, 2] [4, 6, 5, 3] [1] [2, 4, 6, 5, 3] [] [2, 4, 6, 5, 3, 1] IBU 3) 1 c) x, y = [ 1, 2, 3, 4, 5, 6 ], [] print (x, y) while x != [] : y.insert(len(y)//2, x.pop()) print(x, y) VOTA [1, 2, 3, 4, 5, 6] [] [1, 2, 3, 4, 5] [6] [1, 2, 3, 4] [5, 6] [1, 2, 3] [4, 5, 6] [1, 2] [3, 4, 5, 6] [1] [2, 3, 4, 5, 6] [] [1, 2, 3, 4, 5, 6] d) x, y = [1, 2, 3, 4, 5, 6), [] while x !- [] : if x[-1] | 2 == 0: y.insert(0, x.pop()) else: y.append(x.pop()) print(x, y) [1, 2, 3, 4, 5, 6] [] [1, 2, 3, 4, 5] [6] [1, 2, 3, 4] [6, 5] [1, 2, 3] [6, 5, 4] [1, 2] [6, 5, 4, 3] [1] [6, 5, 4, 3, 2] [] [6, 5, 4, 3, 2, 1]
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