Question: The command cvtdq2pd allows you to convert a 4-byte integer to an 8-byte double-precision number as shown in the code below. #include int main(){ int
The command cvtdq2pd allows you to convert a 4-byte integer to an 8-byte double-precision number as shown in the code below.
#includeint main(){ int a; double b; scanf("%d", &a); __asm__( "cvtdq2pd %1, %%xmm0; "movsd %%xmm0, %0;" :"=m"(b) :"m"(a) ); printf("%f ", b); }
Use this command to write inline assembly code where the C program inputs an integer value and a double value, the assembly code finds their sum as a double value, and then the C code outputs their sum. For this, please use the code below and you can only add code with the __asm__ ();. Do not add anything to the C code. For example if the integer input is 4, and the double value input is 3.4, the output should be 7.400000. You can use DevC++ to test and run your code, and you can use the X64 CheatSheet file for help you if want. Copy and paste your final code in the space provided. Don't forget to add -masm=att to the compiler options in DevC++.
#include int main(){ int a; double b; double sum; scanf("%d %lf", &a, &b); __asm__( ADD YOUR ASSEMBLY CODE HERE ); printf("%f ", sum); } Step by Step Solution
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