The compound beam is pin supported at $\backslash ($ M $\backslash )$ and supported by rockers at $\backslash ($ E $\backslash )$ and $\backslash ($ K $\backslash ).$ There is a hinge $($pin$)$ at $\backslash ($ D $\backslash ).$ Suppose that $\backslash ($ X$=2\backslash$mathrm$\{$kN$\}/\backslash$mathrm$\{$m$\}\backslash ).$

Determine the reaction at E$,$ M$,$ and K$.$ Separate your answers with commas.

The supports at E and K are rockers: $\backslash ($ E$\_\{$x$\}=0,$ K$\_\{$x$\}=0\backslash ).$ Supports at M and D are Pin and Hinge. They both have horizontal and vertical reactions.

Hint: start with Free$-$Body Diagram: The compound beam will be dismembered into members EMD and KD$.$ Then apply the equations of equilbrium for each section separatley. start with the easy section.