The conduction heat transfer equation for the cylindrical coordinate system is given below.

$\frac{\text{d}\text{e}\text{l}\text{T}}{\text{d}\text{e}\text{l}\text{t}}=(\frac{de{l}^{2}T}{del{r}^2}+\frac{1}{r}\frac{\text{d}\text{e}\text{l}\text{T}}{\text{d}\text{e}\text{l}\text{r}}+\frac{1}{r^2}\frac{de{l}^{2}T}{\text{d}\text{e}\text{l}{}^2}-\frac{de{l}^{2}T}{del{z}^2}).$

a$)$ Simplify the equation for steady state and radial heat flow.

b$)$ Using the boundary conditions $T=T_1$ at $r=r_1$ and $T=T_2$ at $r=r_2,$ find the temperature distribution in

the radial direction in steady state.

c$)$ Derive the equation that gives the heat flow rate $(qR).$