Question: The CRC algorithm as presented in this chapter requires lots of bit manipulations. It is , however, possible to do them taking multiple bits at

The CRC algorithm as presented in this chapter requires lots of bit manipulations. It is, however, possible to do them taking multiple bits at a time, via a table-driven method, that enables efficient software implementations of CRC. I outline the strategy here for long division 3 bits at a time (See table below); in practice we would divide 8 bits at a time, and the table would have 256 entries.
Let the generator G=1101. To build the table for G, we take each 3-bit sequence p, append three trailing 0's, and then find the quotient q=p000G, ignoring the remainder. The third column is the product of Gq(note: do exclusive-or when adding bits up), the first 3 bits should be equal p.
2.1. Fill in the missing entries in the following table (I did two rows for you already.)
\table[[p,q=p000G,Gq
The CRC algorithm as presented in this chapter

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