The Cross Product for Cartesian Vectors For a = [a 6a, 6a4] and b = [b, 6b, 6b,] then Trick: Write the components of the vectors in 2 rows starting with the 2"d component and repeating it at the end. Take the downward product minus the upward product. Eg.2: Find ax b given a = [36- , 63] and b = [46 6 , ]For collinear vectors, ax b = a b sine 6 where 0 = 22 .. ax b = 2 Combining the dot and cross products: u. x w implies u. |x w | because |u x w would not be defined since the result would be a scalar crossed with a vector. We can use this property to test if 3 vectors are coplanar. If u 6 and w are coplanar, then x w is perpendicular to both and w and since u 6 and w are in the same plane, Eg.3: Determine if the following vectors are coplanar. u = 2696- 4 6 = [36- 46 ] and w = [, 62 6- 4]