Question: The cross - section below is subject to an internal shear load of V _ ( x ) hat ( i ) + V _

The cross-section below is subject to an internal shear load of V_(x)hat(i)+V_(y)hat(j). Determine the shear flow caused by this internal shear load at the midpoint of Leg CD. Leave your expression in terms of Y_(x) and H_(y). The centroid (Z) is located 18mm to the right and 17mm above Node D. Simplify your answer as much as possible.
t_(AC)=t_(BD)=2mm
t_(CD)=t_(DE)=t_(EC)=1mm
L_(AC)=L_(BD)=20mm
L_(CD)=50mm
L_(DE)=30mm
L_(EC)=40mm
\[(V_I)_x =\frac{V_x \cdot I_{xx}- V_y \cdot I_{xy}}{I_{xx}\cdot I_{yy}- I_{xy}^2}\]
\[(V_I)_y =\frac{V_y \cdot I_{yy}- V_x \cdot I_{xy}}{I_{xx}\cdot I_{yy}- I_{xy}^2}\]
\[q(s)= q_0-\int_0^s \left[(V_I)_x \cdot t \cdot x(s^\star)+(V_I)_y \cdot t \cdot y(s^\star)\right]\, ds^\star \]
The cross - section below is subject to an

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