The current balance bridge in Fig $2,$ is used to measure $V_x.$ Assuming D to be a high impedance null detector and $V_{x}Vx=-\frac{V_5}{5}+\frac{V_5(R_4+R_5)}{4R+R_4+R_5}+1R_{5}R=1k,R_4=975,R_5=25,V_S=5VI=10mA{V}_x{V}_x{V}_{x}R5$ :

Show that $at$ null condition, $V_{x}is$ given $by$: $Vx=-\frac{V_5}{5}+\frac{V_5(R_4+R_5)}{4R+R_4+R_5}+1R_5(2$ points$)$

$ii$