the cylinder:

$V=h(\frac{d}{2}{)}^2$ where $his$ the height, and $dis$ the diameter, then calculate the density: $D=\frac{m}{v}$

$V=(24\mathrm{.}44)(\frac{12\mathrm{.}75}{2}{)}^2=(76\mathrm{.}78052445)(6\mathrm{.}375{)}^2$

$=(76\mathrm{.}78052445)(40\mathrm{.}640625)$

$D=\frac{27\mathrm{.}8074}{3120\mathrm{.}408501}$~~$0\mathrm{.}008911461,V=3120\mathrm{.}408501$

Density: $0\mathrm{.}00891146\frac{g}{m}L$

A$2.$ Determine the volume $($in $d{m}^3)$ of a cylinder of the same metal with a mass of $258$ ounces $,$ and $1lb=16oz,$ exactly$).$ The density you calculated in $A1$ is a conversion factor: use dimensional analysis for all steps.

$25802*\frac{11b}{1602}*\frac{453\mathrm{.}59(g)}{116}=$