The decomposition of HI at low temperature was studied by injecting 2.50 mol of HI into a 10.32 L vessel at 25oC. Calculate the concentrations of H2, HI and I2 at equilibrium for the reaction:
2HI(g)⇌ H_2 (g) I_2 (g); K_C= 〖1.26 ×10〗^(-3)HIg⇌ H_2g I_2g; K_C= 1.26 ×10^-3

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Answer Molarity of HI 250 moles 1032L 02422mole... View the full answer