Question: The design challenge at hand involves the task of generating a stable DC voltage from a 9-V battery source. The goal is to provide

The design challenge at hand involves the task of generating a stable DC voltage from a 9-V battery source.

The design challenge at hand involves the task of generating a stable DC voltage from a 9-V battery source. The goal is to provide a 3-V output to power a load resistance represented as R. There are two potential approaches, as shown in Fig. 1, to achieve this: one is to employ a voltage divider circuit using a resistor twice the value of RL, and the other is to use a switched circuit. [A] In the voltage divider circuit, sketch the output voltage across the load resistance R and compute the losses in 2RL. [B] In the switched circuit, determine how frequently the switch needs to toggle on and off to maintain a 3 V output at the load side (R). Sketch the output voltage v (t). [C] What is the power absorbed by the switch for both open and closed conditions? [D] Which circuit is likely more efficient in terms of the power consumed by the element used to regulate the voltage? Hint: Compare the results in part [C] with the losses computed in part [A]. [E] Why is it necessary to use a low-pass filter on the load side in the case of switched circuit? Hint: Compare the output voltage waveform in part [A] and [B]. [F] Repeat part [B] considering the 9-V battery decreased to 6 V. Would the switch need to turn on for a longer duration to maintain the 3 V output on the load side? 9 V ww 2R R 3 V 9V Figure 1: Problem 1

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Based on the information provided in the question and the figure lets address each part sequentially A In the voltage divider circuit left circuit in Figure 1 the output voltage across the load resist... View full answer

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