The differential equation which has $y=C_{1}cos(2x+C_2)$ as its general solution is:

$($a$)y^{\text{'}\text{'}}+4y^{\text{'}}=0$

$($b$)y^{\text{'}\text{'}}-4y=sin4x$

$($c$)y^{\text{'}\text{'}}+4y=0$

$($d$)y^{\text{'}}-4y=0$

$($e$)$ None of the above PLEASE EXPLAIN STEP BY STEP AND SHOW EACH PART OF THR CALCULATION PLEASE. AND EXPLAIN WHY