The differential equation

$y-2y^7=(y^4+6x)y^{\text{'}}$

can be written in differential form:

$M(x,y)dx+N(x,y)dy=0$

where

$M(x,y)=,$ and $N(x,y)=$

The term $M(x,y)dx+N(x,y)dy$ becomes an exact differential if the left hand side above is divided by $y^7.$ The solution of the resulting exact differential equation is $=C.$