The differential equation $y^{\text{'}}=(4x2y3{)}^2$ has the solution

Possible answers.

$2.y=-\frac{(4x3{)}^3}{12}c$

b$.y=-\frac{(4x2y3{)}^3}{12}c$

c$.y=-\frac{(4x2y3{)}^3}{3}c$

d$.y=\sqrt[\phantom{2}]{2}tan(2\sqrt[\phantom{2}]{2}xc)$

e$.4x2y3=\sqrt[\phantom{2}]{2}tan(2\sqrt[\phantom{2}]{2}xc)$