The disk rolls without slipping on the horizontal surface, and at the instant represented, the center O has the velocity v$\_($O$)=2\mathrm{.}8($m$)/($s$)$ and

acceleration a$\_($O$)=5\mathrm{.}6($m$)/($s$^(2))$ with directions shown in the figure. For this instant, the particle A has the indicated speed u$=2\mathrm{.}0($m$)/($s$)$ and

time rate of change of speed u$^()=6\mathrm{.}8($m$)/($s$^(2)),$ both relative to the disk with directions shown in the figure. Determine the absolute velocity

v$\_($A$)$ and acceleration a$\_($A$)$ of particle A$.$

Answers:

v$\_($A$)=(,$i$+$ j$)($ m$)/($s$)$

a$\_($A$)=(,$i$+$ j$)($ m$)/($s$^(2))$