Question: The effective I ( I e f ) value used for deflection calculations is: ( a ) Less than I g because cracking increases the

The effective I (Ief) value used for deflection calculations is:
(a) Less than Ig because cracking increases the bending stiffness of the
beam.
(b) Less than Irr because cracking reduces the bending stiffness of the
beam.
(c) Greater than Ig because the concrete in tension between the cracks adds
to the bending stiffness of the beam.
(d) Greater than Icr because the concrete in tension between the cracks
adds to the bending stiffness of the beam.
(e) None of the other answers is correct.
MPa
mm
When the cross-section shown above is subjected to a positive bending moment,
using dn=233mm, the value of Ia is:
(a) None of the other answers is correct
(b)4502.4106m4
(c)4502.4106mm4
(d)3553.75106m4
(e)3553.75106mm4
Ief=1915106mm4
Ec=30,100MPa
s=1.0 and l=0.6
Permanent load =16kNm
Imposed load =10kNm
effective span of 5.5 m . The total deflection at the midspan, the maximum allowable
deflection and the deflection decision is:
(a) Total deflection =9.8mm; max. allowable deflection =24mm;
:. deflection OK.
(b) Total deflection =11.7mm; max. . allowable deflection =22mm;
:. deflection OK
(c) None of the other answers is correct
(d) Total deflection =11.7mm; max. allowable deflection =11mm;
:. deflection not OK
(e) Total deflection =37.9mm; max. allowable deflection =22mm;
:. deflection not OK
The effective I ( I e f ) value used for

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