The efficiency for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft²). An article gave the accompanying data on tank temperature (x) and efficiency ratio (y).

Temp.172 174 175 176 176 177 178 179

Ratio0.80 1.35 1.38 0.93 1.05 1.10 1 .02 1.74

Temp.182 182 182 182 182 183 183 84

Ratio1.45 1.58 1.67 2.11 2.05 0.86 1.35 0.86

Temp.184 184 184 186 186 187 188 190

Ratio 1.79 1.92 2.66 1.55 2.58 3.02 1.77 2.98

(a) Determine the equation of the estimated regression line. (Round all numerical values to five decimal places.)

y=

(b) Calculate a point estimate for true average efficiency ratio when tank temperature is184. (Round your answer to four decimal places.)

(c) Calculate the values of the residuals from the least squares line for the four observations for which temperature is184. (Round your answers to four decimal places.)

(184,0.86)=

(184,1.79) =

(184,1.92)=

(184,2.66)=

(d) What proportion of the observed variation in efficiency ratio can be attributed to the simple linear regression relationship between the two variables? (Round your answer to four decimal places.)