The electrophilic aromatic substitution of isopropylbenzene with FeBr3, Br2 gives 1-bromo-4-isopropylbenzene. Complete the curved-arrow mechanism below, beginning with formation of the active brominating reagent. Remember to include lone pairs and formal charges where appropriate. ONLY NEED HELP WITH STEPS 3 & 4. NOT SURE WHY, but I can't seem to get the ARROW PUSHING right.

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Include curved arrow(s). +++ Fe -Br: :Br: 0 :Br: bromine and FeBr3. Redraw the product of Br2 and FeBr3 and proceed with the mechanism. Br Br-Fe Br Br :Br Br-Br FeBr For the final two steps of the mechanism, include charges, nonbonding electrons, and curved arrows. :Br + ↑ H ↑ Draw the resulting organic and inorganic species, and then complete the mechanism. X :Br: Map duu HBr :Br Br-FeBr + :Br FeBr3 Include curved arrow(s). +++ Fe -Br: :Br: 0 :Br: bromine and FeBr3. Redraw the product of Br2 and FeBr3 and proceed with the mechanism. Br Br-Fe Br Br :Br Br-Br FeBr For the final two steps of the mechanism, include charges, nonbonding electrons, and curved arrows. :Br + ↑ H ↑ Draw the resulting organic and inorganic species, and then complete the mechanism. X :Br: Map duu HBr :Br Br-FeBr + :Br FeBr3