The ellipse $\frac{x^2}{4}\frac{y^2}{9}=1$ is shifted up $3$ units and right $7$ units. Find an equation for the new ellipse, and find the new foci, vertices, and center.

Choose the correct equation for the new ellipse below.

A$.\frac{(x-3{)}^2}{4}\frac{(y-7{)}^2}{9}=1$ B$.\frac{(x7{)}^2}{4}\frac{(y3{)}^2}{9}=1$

C$.\frac{(x3{)}^2}{4}\frac{(y7{)}^2}{9}=1$ D$.\frac{(x-7{)}^2}{4}\frac{(y-3{)}^2}{9}=1$